3v^2+6v-45=0

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Solution for 3v^2+6v-45=0 equation: 



3v^2+6v-45=0

a = 3; b = 6; c = -45;
Δ = b2-4ac
Δ = 62-4·3·(-45)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$


$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-24}{2*3}=\frac{-30}{6}
=-5
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+24}{2*3}=\frac{18}{6}
=3
$

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